How to draw a conclusion in motherless parentage testing using short tandem repeats as genetic makers.
- Author:
Yun-Liang ZHU
1
;
Yan-Mei HUANG
;
Xin-Yao WU
Author Information
1. Department of Forensic Medicine, SUN Yat-sen University, Guangzhou 510080, China. zhuyunliang@hotmail.com
- Publication Type:Journal Article
- MeSH:
Algorithms;
Alleles;
Binomial Distribution;
Forensic Genetics/methods*;
Gene Frequency;
Genetic Markers;
Humans;
Male;
Mutation;
Paternity;
Probability;
Tandem Repeat Sequences
- From:
Journal of Forensic Medicine
2006;22(4):281-284
- CountryChina
- Language:Chinese
-
Abstract:
OBJECTIVE:To calculate the exclusion power of STR loci in motherless parentage testing and to discuss how to draw a conclusion if there are inconsistent loci.
METHODS:Based on the law of inheritance and allele frequency, the powers of exclusion of STR loci in motherless parentage testing (PE(M)) were calculated. Based on the mean PE(M) and mutation rate of 13 CODIS loci. The probabilities of inconsistence under paternity and non-paternity were calculated respectively according to binomial theorem.
RESULTS:The PE(M) of locus having co-dominate alleles could be calculated as: PE(M) = (i = 1)sigma (n) p i 2(1-p (i))2+ (i < j)sigma (n) 2p (i)p (j)(1-p (i)-p (j))2. According to the formula, the average PE(M) of 13 CODIS was 0.411. Based on the mean PE(M) and mutation rate, the likelihood ratio of true father to random man (paternity index) was got using binomial theorem.
CONCLUSION:The conclusion in motherless parentage testing could be drawn based on the likelihood ratio (paternity index) derived from mean PE(M) and mutation ratio.
